999.111=3n^2

Solution for 999.111=3n^2 equation:

999.111=3n^2

We move all terms to the left:

999.111-(3n^2)=0

a = -3; b = 0; c = +999.111;
Δ = b2-4ac
Δ = 02-4·(-3)·999.111
Δ = 11989.332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{11989.332}}{2*-3}=\frac{0-\sqrt{11989.332}}{-6}
=-\frac{\sqrt{}}{-6}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{11989.332}}{2*-3}=\frac{0+\sqrt{11989.332}}{-6}
=\frac{\sqrt{}}{-6}
$